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n^2-2n-624=0
a = 1; b = -2; c = -624;
Δ = b2-4ac
Δ = -22-4·1·(-624)
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2500}=50$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-50}{2*1}=\frac{-48}{2} =-24 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+50}{2*1}=\frac{52}{2} =26 $
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